Question

plz anyone say me the answer​

Answer 1

Answer:

d) log x

Hope this helps u

Answer 2

Step-by-step explanation:

∫x log x dx = (x^2/2) log x -x^2/4 + c

Proof : Using integration by parts,

∫udv = uv - ∫vdu

In ∫ x log x dx,

take, u=logx => du= (1/x) . dx

∫dv=∫x dx => v=x^2/2

Now substituting,

∫x log x = logx (x^2/2) - ∫x ^/2 . (1/x) dx = logx (x^2/2) - (1/2)∫dx= (x^2/2) log x -x^2/4 + c

where c is constant.

Cheers,

KSAM