Question

plz anyone tell about this​

Answer 1

Answer:

I don't know

Step-by-step explanation:

please mark me as brain least I

Answer 2

Answer:

∠DCB = 125° (Opp angles on parallelogram)

∠DCB = y + 56 = 125

y = 125 - 56

y = 69

WKT,

all angles of quadrilateral= 360

∠A∠B∠C∠D = 360

125+ b +125 + b = 360 (b=d since Opp angles on parallelogram are equal)

2b = 360-250

2b = 110

b = 55

Angle ABC and x = 55 each

To find angle x, we need to find the 3rd angle of the triangle BCE

WKT,

B+C+E = 180

55+56+E = 180

E = 180-111

E = 69

180-69 = 111

therefore x = 111