plz anyone tell me the ans if you are sure
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here is your answer by Sujeet,
Given à and b are zeroes of polynomial,
x²-5
b=-√5
a=√5
Again,
value of 1/a+1/b
a+b/ab
√5+(-√5) / √5*-√5
√5-√5 / -5
0/5
0
that's all
Given à and b are zeroes of polynomial,
x²-5
b=-√5
a=√5
Again,
value of 1/a+1/b
a+b/ab
√5+(-√5) / √5*-√5
√5-√5 / -5
0/5
0
that's all
Ajmi:
ook
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