plz buddy solve this
right answe = Mark as brainlist
wrong answer=reported
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answer for the given problem is given
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a) As CF is a straight line
⇒∠COB+∠BOA+∠AOF=180
⇒4x+30+2x=180
⇒6x+30=180
⇒6x=150
⇒x=25°
∠BOC=4x
∠BOC=4(25)
∠BOC=100°
b) As DA is a straight line
∠BOA+∠BOC+∠COD=180
⇒30+100+y=180
⇒130+y=180
⇒y=50°
c) As BE and DA are straight lines
⇒∠BOA=∠DOE
∠DOE=30°
d) As BE and CF are straight lines
⇒∠BOC=∠EOF
∠EOF= 100°
e) ∠FOA=2x
x= 25
2x=2(25)
∠FOA=50°
FOLLOW AND MARK AS BRAINLIEST
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