Question

plz can anyone answer the 12th one ​

Answer 1

Answer:

Sorry, but it's not clear.....

Answer 2

Answer:

Given: ABC is a triangle, PQ , BC

AD is the median which cuts PQ at R.

To prove : AD bisect PQ at R.

Proof: In triangle ABD PR||BD

AP = AR

In triangle ACD RQ||DC

AR = AQ

In triangle APR and ABD

angle APR = ABD

angle ARP = ADB

triangle APR is similar to triangle ABD ( AA Similarity)

AP = AR = PR

Similarly triangle ARQ is similar to triangle ADC

AQ = AR = RQ

According to both Equation

AR = PR = RQ

but BD = DC

PR = RQ

or AD bisect PQ at R

HOPE IT HELPS YOU.

PLZZ MARK ME AS A BRAINLIST...