Question

plz can anyone do the middle term??​

Answer 1

Answer:

(7a-5)(2a+1)

Step-by-step explanation:

-14a^2+3a+5

taking minus as common then it becomes,

14a^2-3a-5

14a^2-10a+7a-5

2a(7a-5)+1(7a-5)

(7a-5)(2a+1)

Answer 2

$\huge\green{A}\red{N}\orange{S}\pink{W}{E}\blue{R}$

$(i) \: \: \: 6 {x}^{2} + 7x + 5$

6×5=30

30= -3-(-10)

$= 6 {x}^{2} - 3x - 10x + 5$

$= 3x(2x - 1) - 5(2x - 1)$

$= (2x - 1)(3x - 5)$

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$(ii) \: \: \: \: - 14 {a}^{2} + 3a + 5$

-14×5= -70

-70= -3-(-10)

$= - 14 {a}^{2} - 10a - 7a + 5$

$= 2a(7a - 5) - 1(7a - 5)$

$= (7a - 5)(2a - 1)$

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