Question

plz can anyone solve this.

Answer 1

Area of quadrilateral ABCD= Area ∆ ABD +Area ∆ BDC
Area ∆ ABD = 1/2× 14 × 48 =336cm²
Area ∆ BDC :-
s= a+b+c /2 where, a= 112cm, b= 78cm and c=50cm
s= 112+78+50 /2 = 120cm
Area = √s(s-a) (s-b) (s-c)
= √120(120-112)(120-78)(120-50)
= √120(8)(42)(70)
= √2822400
Area ∆ BDC= 1680cm²
Now area of quadrilateral = 1680+336=2016cm²

Answer 2

Hope it helps uhh!! Sis ✌
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