Question

Plz can anyone solve this​

Answer 1

P = VI

I = $\frac{V} {P}$

I = $\frac{220}{ 40}$

I = $\frac{11}{2}$

$\red{ \boxed{I = 5.5 Ampere} }$

V=IR

R = $\frac{220 × 2}{11 }$

R = $\frac{ 440}{11}$

${\orange{\boxed{R = 40 ohm}} }$

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New Bulb

I = $\frac{220}{25 }$

I = $\frac{ 44}{5}$

$\red{\boxed{I = 8.8 Ampere}}$

R = $\frac{220×5}{44 }$

R = $\frac{1100 }{44}$

$\orange{ \boxed{R = 25 ohm} }$