Question

plz can anyone solve this for me ​

Answer 1

Answer:

1

Step-by-step explanation:

log ₁.₄₃₃₃₃ (43/30) = x

=> (1.4333...)^x = 43/30

=> (1.4333...)^x = 1.43333....

=> x = 1

Note:

You can also evaluate 1.43333... like follows

let a = 1.4333.....

=> 100a = 143.3333...

=> 10a    = 14.3333....

=> 100a-10a = 143.333.. - 14.3333..

=> 90a = 129

= a = 129 / 90  = 43*3 / 30*3 = 43/30

hence our question, log ₁.₄₃₃₃₃ (43/30) = x  becomes

                                 log ₄₃/₃₀ (43/30)

                                = 1           [∵ logₐ a = 1]

=>                      x = 1