Math, asked by Rohitkumarsahu144, 11 months ago

plz can u do this
indeed the answer
plz do it As fast as possible​

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Answers

Answered by RvChaudharY50
13

Solution :-

Given :-

a = b^x

→ b = c^y

→ a = c^z

Solving 3rd ,

a = c^z

putting value of a in LHS, we get,

→ b^x = c^z

putting value of b in LHS now,

→ (c^y)^x = c^z

using (a^b)^c = (a)^(bc) in LHS now,

→ c^(yx) = c^z

using , if a^b = a^c than b = c now, we get,

→ xy = z . (Proved).

Answered by Abhishek474241
3

Given

Three values

\sf\:a=b^x\\b=c^y\\and\:a=c^z

To show.

Z= xy

Solution

Let the given values as Equation (1), (2) and (3)

\sf\:a=b^x\rightarrow{1}\\b=c^y\rightarrow{2}\\and\:a=c^z\rightarrow{3}

Now from equation (1) and (3)

\sf\:a=b^x\rightarrow{1}\\and\:a=c^z\rightarrow{3}

\implies\:b^x=c^z\rightarrow{4}

Now putting value of Equation (2) in (4)

\implies\:C^{xy}=c^z

Now same base C

Therefore

XY=Z

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