Question

Plz can unswerving for this alone it is power lesson

Answer 1

Step-by-step explanation:

$we \: have \: to \: prove \: \frac{ {(x}^{ - 1} + {y}^{ - 1} )}{(x + y)} = {(xy)}^{ - 1} \\ on \: taking \:left \: hand \: side \: \frac{ {(x}^{ - 1} + {y}^{ - 1} )}{(x + y)} \: \\ = > \frac{(\frac{1}{x} + \frac{1}{y} )}{(x + y)} \\ = > \frac{( \frac{y + x}{xy} )}{(x + y)} \\ = > \frac{( \frac{x + y}{xy} )}{(x + y)} \\ \\ = > \frac{1}{xy} \\ = > {x}^{ - 1} \times {y}^{ - 1} \\ = > {(xy)}^{ - 1} \\ = > right \: hand \: side \: \\ hence \: proved$