Math, asked by softly, 1 year ago

plz... can you help me frndz??? plz do the middle term splitting....! ​

Attachments:

Answers

Answered by PATHONS
3

firstly multiple the first term to the second term

than see that

the number which is multipled ex-

x.2 it will 2 and the middle term is X it will

2-1

Answered by SunitaWilliams
23

(1) 6x^2 -x -1

6x^2 + 2x -3x -1 = 0

2x( 3x + 1) - 1(3x + 1) = 0

(2x - 1)(3x+ 1) = 0

》 2x - 1 = 0

2x = 1

x = 1/2

》 3x +1 = 0

3x = -1

x = -1/3

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = - b/a

1/2 + (- 1/3) = -(-1)/6

1/2 - 1/3 = 1/6

3-2/6 = 1/6

1/6 = 1/6

LHS = RHS

product of the zeroes = c/a

1/2 × -1/3 = -1/6

-1/6 = -1/6

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

====================

(2) 25x (x + 1) + 4

25x^2 + 25x + 4 =0

25x^2 + 5x + 20x + 4 =0

5x( 5x + 1)+4 ( 5x +1)=0

(5x + 4 )(5x + 1) = 0

》 5x + 4 = 0

5X = -4

X = -4/5

》 5x + 1 = 0

5x = - 1

x = -1/5

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = -b/a

-4/5 + (-1/5) = -25/25

-4/5 -1/5 = -25/25

-20-5/25= -1

-25/25 = -1

-1 = -1

LHS= RHS

product of zeroes = c/a

-4/5 × (-1/5)= 4/25

4/25 = 4/25

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

====================

(3) 4x^2 + 4x + 1

4x^2 + 2x + 2x + 1 = 0

2x ( 2x + 1)+1 (2x + 1) =0

(2x + 1)(2x +1)=0

》2x = -1

x = -1/2

(in both cases the answer is same )

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = -b/a

-1/2 + (-1/2) = -4/4

-1/2 -1/2 = -1

-2-2/4 = -1

-4/4 = -1

-1 = -1

LHS= RHS

product of zeroes = c/a

-1/2 × (-1/2) = 1/4

1/4 = 1/4

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

====================

(4) 48y^2 - 13y -1=0

48y^2 + 3y -16y -1=0

3y (16y + 1) -1 (16y +1) =0

(3y -1)(16y+1) = 0

》3y -1 =0

3y = 1

y = 1/3

》16y +1 =0

16y = -1

y = -1/16

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = - b / a

1/3 + (-1/16) = -(-13/48)

16-3/48 = 13/48

13/48 = 13/48

LHS = RHS

product of the zeroes = c / a

1/3 × (-1/16) = -1/48

-1/48 = -1/48

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

===================

(5) 63 -2x -x^2

x^2 +2x -63 = 0

x^2 +9x -7x-63 =0

x (x + 9) -7 (x+9) = 0

( x-7)(x+9) = 0

》 x-7 = 0

X = 7

》x+9 =0

X = - 9

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = - b / a

7+(-9) = -2/1

-2 = -2

LHS = RHS

product of the zeroes = c / a

7× (-9) = -63/1

-63 = - 63

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

====================

(6) 2x^2 - 5x = 0

X(2x -5) = 0

》x = 0

》2x - 5 = 0

2x = 5

x = 5/2

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = - b / a

0 + 5/2 = -(-5/2)

5/2 = 5/2

LHS = RHS

product of the zeroes = c / a

0 × 5/2 = 0/5

( °•° 'c' term is absent so we take it as zero)

0 = 0

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

================

(7) 49x^2 - 81 =0

49x^2 = 81

x^2 = 81/49

x = under root 81/49

x = +-9/7

The two zeroes are +9/7 and -9/7

Verifying the relationship between zeroes and coefficients.

sum of the zeroes = - b / a

9/7 + (-9/7) = -0/49

0=0

LHS = RHS

product of the zeroes = c / a

9/7 × -9/7 = -81/49

-81/49 = -81/49

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.

======================

(8) 4x^2 -4x -3 =0

4x^2 +2x -6x-3 =0

2x ( 2x + 1)-3 (2x+1) =0

(2x - 3)(2x + 1 ) = 0

》2x -3=0

x = 3/2

》2x + 1 = 0

x = -1/2

Verifying the relationship between zeroes and coefficients

sum of the zeroes = - b / a

3/2 +(-1/2) =-(-4)/4

2/2 = 1

1=1

LHS = RHS

product of the zeroes = c / a

3/2 × (-1/2) = -3/4

-3/4 = -3/4

LHS = RHS

•°•The relationship between zeroes and coefficients is verified.


MsPRENCY: O_O Well done @dii ✌ Feeling tired after scrolling the screen :joy: Great work.. Keep it up ✌
Anonymous: Long answer xD
Anonymous: I mean Great* xD
MoonGurl01: Awesome Work Buddy..☺ Keep Rocking ..✌
Anonymous: Extraordinary work ❤
SunitaWilliams: Thanks alot @everyone
Anonymous: Awesome !! ❤
SunitaWilliams: Thanks @Dahiya...♥
Similar questions