Question

plz complete the table​

Answer 1

Explanation:

A. KCl + AgNO3 gives white precipitate.

Reaction: KCl + AgNO3 = KNO3 + AgCl

AgCl (Silver chloride) produces white colour, hence, it infers that chloride (Cl-) is present.

B. RI + AgNO3 gives light yellow precipitate.

Reaction: RI + AgNO3 = RNO3 + AgI

where R = Alkyl group

AgI (Silver iodide) produces light yellow colour, hence, it infers that iodide (I-) is present.

C. Pb(NO3)2 + 2KI gives bright yellow precipitate.

Reaction: Pb(NO3)2 + 2KI = 2KNO3 + PbI2

PbI2 (Lead iodide) produces bright yellow colour, hence, it infers that lead iodide (PbI2) is present.