Question

Plz Differentiate it


It is urgent

Answer 1

$\huge \bf{ \red{hey}}$


$\huge{ \mathfrak{ \pink{here \: is \: answer}}}$

please see in pic

$\huge \boxed{ \boxed{ \orange{hop \: it \: helps}}}$

$\huge{ \purple{thanks}}$

Answer 2

$log(xy) = log \: {e}^{(x - y)} \\ log(xy ) = (x - y) log(e \\ log(x ) + log(y) = (x - y)(1) \\ log(x) + log(y) = (x - y) \\ d \frac{ log(x) + log(y)) }{dx} = \frac{d( x - y)}{dx } \\ \frac{d( log(x) }{dx} + \frac{d( log(y) }{dx} = \frac{d(x)}{dx} - \frac{d(y)}{dx} \\ \frac{1}{y} + \frac{d log(y) }{dx} . \frac{dy}{?dy} = 1 - \frac{dy}{dx} \\ \frac{1}{y} + \frac{d( log(y) }{dy} . \frac{dx}{dx} = 1 - \frac{dy}{dx} \\ \frac{1}{y} + \frac{1}{y} . \frac{dy}{dx } = 1 - \frac{dy}{dx} \\ \frac{1}{y} . \frac{dy}{dx} + \frac{dy}{dx} = 1 - \frac{1}{?x} \\ \frac{dy}{dx}( \frac{1 + y}{y} = ( \frac{x - 1}{x} \\ \frac{dy}{dx } = ( \frac{x - 1}{x} ). \frac{y}{1 + y} ) \\ \frac{dy}{dx} = \frac{y(x - 1)}{x(1 + y)}$

Hope it will help you ☺❤☺