Question

plz differentiate this asap.
y= ax+b/cx+d.

Answer 1

Heya

$y = \frac{ax + b}{cx + d}$

Now, multiply and divide by : c / a

$y = \frac{cx + \frac{bc}{a} }{(c/a)(cx + d)}$

Add and subtract 'd' in numerator :
$y = 1 + \frac{ bc-ad}{c(cx + d)}$

Differentiate using chain rule :
$\frac{dy}{dx} = 0 + \frac{ -c( bc - ad ) }{ {c(cx + d)}^{2} }$

Hence, the required derivative is :
$\frac{ ad - bc }{ {(cx + d)}^{2} }$