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Given to us,
focal length of the convex lens = 6 cm
distance from object to lens (u ) = 4 cm
height of object = 0.5 cm
height of image = ??
By lens formula,
1/f = 1/v - 1/u
1/f + 1/u = 1/v
1/6+1/-4 = 1/v
1/v = 1/6-1/4
= 4 - 6/6*4
= -2/24
V =24/-2 = -12 cm
m = h'/h = v/u
H'/0.5 = -12/-4
= 3
H' = 3*0.5
=1.5 cm.
Nature of image formed :-
- virtual .
- upright .
- magnified .
Hope it helps...please mark as brainliest.
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