Question

plz do in paper
urgent plzzzzzz​

Answer 1

Answer:

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Answer 2

$x = 3 + \sqrt{2} \\ x = 1 + 2 \sqrt{2} + \sqrt{2} \\ x = ({1 + \sqrt{2} )}^{2} \\ now \\ \sqrt{ x} - \: {x}^{ - \frac{1}{2} } \\ putting \: the \: bove \: value \\( 1 + \sqrt{2} ) - \frac{1}{1 + \sqrt{2} } \\ 1 + \sqrt{2} - (\frac{1 - \sqrt{2} }{(1 - \sqrt{2})(1 + \sqrt{2}) } \\ 1 + \sqrt{2} + 1 - \sqrt{2} \\ 1 + 1\\ 2</p><p></p><p>.</p><p></p><p></p><p>$