Physics, asked by aarushchoudhary59, 5 months ago

plz do it fast guys​

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Answers

Answered by Anonymous
1

Explanation:

Q. A ball is thrown up with a velocity of 15m/s.How high will it go before it begin to fall again.

iss question ka answer h ye

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Answered by jaymishra200412
4

Answer:

v {}^{2}  = vo {}^{2}  + 2ad

v {}^{2}  = (0) {}^{2}  + 2 \times 10 \times 20

v {}^{2}  = 400

(v = 20)

v = vo  + at

20 = 0 + 10t

20 = 10t

(t = 2)

i hope you like this answer bro

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