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Heya Dear !
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13)
As you know complete angle forms 360°
so, 2x + 90 + x = 180 {LPA}
3x + 90 = 180
3(x+30 ) = 180
x + 30 = 60
x = 30 °
As ∠DOE = 90 °
and ∠DOE + ∠EOC = 180 {LPA}
so, ∠EOC = 90°
∠EOC = x + y
90 = 30 + y
y = 90 - 30 = 60°
and y + z = 180 {LPA}
60 + z = 180
z = 180 - 60 = 120 °
14) .
in the given figure
∠COE = ∠DOF = 6x {VOA}
∠AOE = BOE = 8 x {VOA}
and
8x + 6x + 4x = 180 {LPA's }
18 x = 180
x = 10
so, 8x + 6x + y = 180 {LPAs}
14x + y = 180
140 + y = 180
y = 180 -140 = 40 °
15) .
if x + y = 180 then it forms a straight line lets check
I) x = 63 , y = 117
yes , it forms a straight line as 63 + 117 = 180
ii) x = 58 , y = 132
No , It does not form any straight line because its angle ≠ 180 => 58 + 132 = 190
iii) x = 4/5 right angles , y = 98
x = 4/5 x 90 , y = 98
x = 72 , y = 98
no it doesn't form straight line because x + y ≠ 180 ,
______________________________________________________________
13)
As you know complete angle forms 360°
so, 2x + 90 + x = 180 {LPA}
3x + 90 = 180
3(x+30 ) = 180
x + 30 = 60
x = 30 °
As ∠DOE = 90 °
and ∠DOE + ∠EOC = 180 {LPA}
so, ∠EOC = 90°
∠EOC = x + y
90 = 30 + y
y = 90 - 30 = 60°
and y + z = 180 {LPA}
60 + z = 180
z = 180 - 60 = 120 °
14) .
in the given figure
∠COE = ∠DOF = 6x {VOA}
∠AOE = BOE = 8 x {VOA}
and
8x + 6x + 4x = 180 {LPA's }
18 x = 180
x = 10
so, 8x + 6x + y = 180 {LPAs}
14x + y = 180
140 + y = 180
y = 180 -140 = 40 °
15) .
if x + y = 180 then it forms a straight line lets check
I) x = 63 , y = 117
yes , it forms a straight line as 63 + 117 = 180
ii) x = 58 , y = 132
No , It does not form any straight line because its angle ≠ 180 => 58 + 132 = 190
iii) x = 4/5 right angles , y = 98
x = 4/5 x 90 , y = 98
x = 72 , y = 98
no it doesn't form straight line because x + y ≠ 180 ,
Saanvipriya:
thank you sooooo much
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