Question

plz do it fast
it is from class 10 ELECTRICITY​

Answer 1

Answer:

It looks like in series combination but really it is in parellel combination.

Explanation:

Given=> I=1.0 A

R1= 4 ohm

R2= 16 ohm

R3= 8 ohm

In parallel combination,

1/R=

$\frac{1}{4} + \frac{1}{8} + \frac{1}{16} = \frac{14}{32}$

so, R=

$\frac{32}{14} ohm = \frac{16}{7} ohm$

Let current flowing from 4 ohm resistor be I1,

from 16 ohm resistor be I2 & from 8 ohm resistor be I3

By putting values,

I1=V/R1= 4/7 A

I2=V/R2= 1/7 A

I3=V/R3= 2/7 A