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Ethanoic acid is warmed with ethanol in the presence of a few drops of concentrated sulphuric acid a sweet smelling Ester called ethyl ethanoate is formed.
CH3COOH + C2H5OH ----Conc.H2SO4→ CH3COOH + H2O
This reaction to form an ester is called esterification. This reaction is also used as a test for ethanoic acid.
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Answer: C2H5OH(l)+CH3COOH(l)−→−−Conc.H2SO4CH3COOC2H5(l)+H2O(l)
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