Math, asked by itsmehakkaur161, 7 months ago

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Answered by Vishwaabhi
1

Answer:

1) (a+b) (a-b) = a^2 -ab +ab - b ^2 = a^2 - b^2

2). (x+3)(x-2) =x^2 -2x +3x -6 = x^2 +x- 6

3). (2a+3b) (3a+4b) = 6a^2 +8ab + 3ab +12b ^2

= 6a^2 b +11ab +12b^2

4). -a × -a^2 × a^3 = a ^(1+2+3) = a^6

5). (5a+4b) (2a+3b) = 10a^2 + 15 ab + 8ab + 12b^2

= 10 a^2 + 23 ab + 12b^2

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Thanks

Answered by wwwanweshamodi17
1

Answer:

1)= a(a - b) + b(a - b) \\  =  {a}^{2}  - ab + ab -  {b}^{2}  \\   = {a}^{2}  -  {b}^{2}

2) = x(x - 2) + 3(x - 2) \\  =  {x}^{2}   - 2x + 3x - 2 \\  =  {x}^{2}  + x - 2

3) = 2a(3a  + 4b) + 3b(3a  + 4b) \\  = 6 {a}^{2}  + 8ab + 9ab + 12 {b}^{2}  \\  = 6 {a}^{2} + 17ab + 12 {b}^{2}

4) = ( - a) \times a \times a \\  = ( - a)

5) = 5a(2a + 3b) + 4b(2a + 3b) \\  = 10 {a}^{2}  + 15ab + 8ab + 12 {b}^{2}  \\  = 10 {a}^{2} + 23ab + 12 {b}^{2}

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