Question

plz do question 2 will mark as brainiest

Answer 1

Answer:

Here's your answer

Step-by-step explanation:

I am using Q as theta

=> √sec²Q + cosec²Q

=> √1/cos²Q + 1/sin²Q

=> √sin²Q + cos²Q/cos²Q . sin²Q

=> √1/cos²Q . sin²Q     (sin²Q + cos²Q = 1)

=> 1/cosQ . sinQ

=> cos²Q + sin²Q/cosQ . sinQ

=> cosQ/sinQ + sinQ/cosQ

=> cotQ + tanQ

=R.H.S

Hope you understand.

Answer 2

Answer:

Refer to the attachment

hope this helps you...