plz do sum for meq 5
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Area of the circle with radius 4 cm = πr² = π(4)² = 16 π cm²
Area of the circle with radius 3 cm which is removed = π(3)² = 9π cm²
Remaining area = 16π - 9π = 7π = 7 x 3.14 = 21.98 cm²
Hope This Helps You!
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Area of the circle with radius 3 cm which is removed = π(3)² = 9π cm²
Remaining area = 16π - 9π = 7π = 7 x 3.14 = 21.98 cm²
Hope This Helps You!
❤️
anu140903:
ur welcome
can u plz mark it as brainlist!!
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