Question

plz do the answer with process​

Answer 1

Given:-

• ΔQ = 800J
• P = 1 atm
• ΔV = 14-4 = 10lit

To Find:-

Change in the internal Energy(ΔU)

Explanation:-

w.k.t,

$\blue{\boxed{\pink{ΔQ = ΔU + ΔW}}}$

$\green{\boxed{\red{ΔW = PΔV}}}$

${\rightarrow}\: 800J = ΔU + (1 \: atm) (10 \: lit)$

${\rightarrow}\: 800 J= ΔU + 10\: atm.lit$

${\rightarrow}\: 800 J= ΔU + 10 atm.lit \times 101.33 \:$

${\rightarrow}\: 800 J= ΔU +1013.3 J$

${\rightarrow}\: ΔU = 800 J - 1013.3 J$

${\rightarrow}\: \bold{ΔU =-213.3 J }$

Extra Information:-

• ΔQ is +ve when, heat is absorbed by the system and vice versa

• ΔW is +ve when, work is done by the gas and vice versa

Answer 2

Answer:

w=-2.303nRT㏒v2/v1

Explanation: