plz do the question 7
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Answer:
ANSWER IS C PLEASE MARK ME
Step-by-step explanation:
In quadrilateral ABCD,
∠A+∠B+∠C+∠D=360
o
--- ( 1 ) [ Sum of angles of quadrilateral is 360
o
]
In △CED,
⇒ ∠CED+∠EDC+∠ECD=180
o
[ Sum of angles of triangle is 180
o
. ]
⇒ ∠CED+
2
1
∠D+
2
1
∠C=180
o
⇒ 2∠CED+∠D+∠C=360
o
----- ( 2 )
From ( 1 ) and ( 2 ),
⇒ 2∠CED+∠D+∠C=∠A+∠B+∠C+∠D
⇒ 2∠CED=∠A+∠B
⇒ ∠A+∠B=2∠CED
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