plz do this and post a picture
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CD = 4,DB = 6
So by Pythagorean theory
BC square = CD square + DB square
So BC = root 52
AD = 3 ,CD= 4
So AC = 5 by Pythagorean theory
Tan B = CD / DB
= 2/3
Sin A = CD /AC
= 4/5
Cot A = AD/CD
=4/3
Sin square B + cos square B
=1
(By formula)
So by Pythagorean theory
BC square = CD square + DB square
So BC = root 52
AD = 3 ,CD= 4
So AC = 5 by Pythagorean theory
Tan B = CD / DB
= 2/3
Sin A = CD /AC
= 4/5
Cot A = AD/CD
=4/3
Sin square B + cos square B
=1
(By formula)
Sanjana5428:
Hey sry,
why?
Anyways we don't require BC in answer
No need 2 write it.
ok
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