Question

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Answer 1

Step-by-step explanation:

Given,

Area of Square = 64 m².

s² = 64

s = √64

s = 8 m.

Perimeter = 4 * Side

                = 4 * 8

               = 32 m.

Also, Given:

Length of rectangle is twice the breadth.

l = 2b   ------- (1)

Perimeter of rectangle = 2(l + b)

= 2(2b + b)

= 2(3b)

= 6b

Perimeter of Square is equal to that of rectangle.

⇒ 32 = 6b

⇒ b = 32/6

Then,

l = 2(32/6)

l = 32/3

Now,

Area of rectangle = l * b

=> 32/3 * (32/6)

=> 56.6 m

Hope it helps!

Answer 2

Step-by-step explanation:

given,area of square is 64m^2

area of square = l^2

let, side of square is X

64 = X^2

X = 8 cm ( taking square roots)

perimeter of square is 4×l

=4× 8

=32 cm.

In rectangle,

let, breadth of rectangle is X

by given condition,

length is 2X.........(1)

by second condition

perimeter of rectangle=2(l+b)

=2(2X+X)

32=2×3X

32=6x

X=32/6

=16/3

x =16/3cm. breadth is 16/3

2x=16/3

X=16/3×2

therefore, length is 32/2

now, area of rectangle= l× b

=32/2 × 16/3

=32 × 4/3

=128/3

=42.66

=42.67cm^2