Question

plz do this ques step by step.....ques 8

Answer 1

${x}^{2} - 3x + q = 0 \\ \alpha + \beta = 3 \\ 2 \alpha + 2 \beta = 6 \\ 2 \alpha + 3 \beta = 15 \\ \beta = 9 \\ \alpha = - 6 \\ {x}^{2} - 3x + q = 0 \\ { (- 6)}^{2} - 3 \times ( - 6) + q = 0 \\ 36 + 18 + q = 0 \\ q =- 54$
Substitute any value of beta or alpha to get the value of q.
Mark it as the brainliest answer.