Math, asked by jashan200336, 11 months ago

plz do this question

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Answered by amitkrsen
1

27 {a}^{3}  +  \frac{1}{64 {b}^{3} }  +  \frac{27 {a}^{2} }{4b}  +  \frac{9a}{16 {b}^{2} }  \\ 27 {a}^{ 3 }  +  \frac{27 {a}^{2} }{4b}  +  \frac{9a}{16 {b}^{2} }  +  \frac{1}{64 {b}^{3} }   \\  {(3a)}^{3}  + 3 {(3a)}^{2}  \frac{1}{4b}  + 3(3a) {( \frac{1}{4b} )}^{2}  +   {( \frac{1}{4b} )}^{3}  \\  {(3a +  \frac{1}{4b} )}^{3}
Answered by arnab2261
1
Hope u may understand the writing.

If helps, please mark it as brainliest ^_^
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