plz do this question i will mark brainliest
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L.H.S.
(1+cosA/sinA-1/sinA)(1+sinA/cosA+1/cosA)
(sinA+cosA-1)/sinA(cosA+sinA+1)/cosA
[ (sinA+cosA)²-1²]/sinAcosA. [a²-b²=(a+b)(a-b)]
[sin²A+cos²A+2sinAcosA-1]/sinAcosA
(1+2sinAcosA-1)/sinA cosA
2sinAcosA/sinAcosA
2=R.H.S.
PLEASE MARK AS BRAINLIEST ANSWER
gauravmahore:
maine kya mistake ki jo aapne mera answer ko brainliest mark nhi kiya
☺️your method is so good :-) bro
to phir bhi aapne brainliest mark nhi kiya
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=> 1+tan A+sec A+cot A+cot A.tan A+cot A.sec A -cosec A-tan A.cosec A- sec A.cosec A
=>1+tan A+sec A+cot A+1+cosec A-cosec A-sec A-sec A.cosec A
=>2+tan A+cot A- sec A.cosec A
=>2+sin²A+cos²A/cos A.sin A - sec A.cosec A
=>2+1/cos A.sin A- sec A.cosec A
=>2+sec A.cosec A-sec A.cosec A
=> 2+0
=> 2
RHS
=>1+tan A+sec A+cot A+1+cosec A-cosec A-sec A-sec A.cosec A
=>2+tan A+cot A- sec A.cosec A
=>2+sin²A+cos²A/cos A.sin A - sec A.cosec A
=>2+1/cos A.sin A- sec A.cosec A
=>2+sec A.cosec A-sec A.cosec A
=> 2+0
=> 2
RHS
thanks
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