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Answer:
the current in the circuit is 0.15 amp
Explanation:
30 ohm ,15 ohm and 15 ohm connected in series
so R1= 30+15+15
= 60 ohm
then 30 ohm is connected in series with R1
total resistance 1/R= 1/R1+1/R2
= 1/60+1/30
1/R= 3/60
R= 60/3=20 ohm
Voltage V= 3 volts
I= V/R
= 3/20
= 0.15 amp
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