Question

plz don't say wrong ans​

Answer 1

Given:-

DE || BC

So,

∆ADE ~ ∆ABC by AA criteria .

By B.P.T,

$\: \: \: \: \: \: \frac{AD}{AB} = \frac{DE}{BC} \\ = > \frac{2}{3} = \frac{3}{BC} \\ = >BC = \frac{3 \times 3}{2} \\ = BC = \frac{9}{2}$

Answer 2

Answer:

OK I will never say wrong answers