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a) u = 0 m/s
t = 30 sec
a = 5m/s²
v = u + at
v = 0 + 30×5
v = 150m/sec
v² - u² = 2as
(150)² - 0² = 2 × 5 × s
(150)² = 10s
s = 22500/10
s = 2250 m
speed gained = 150m/sec
distance = 2250m
b) t = 2min = 120 sec
s = 140m
avg speed = total distance/ total time
= 140/120
= 7/6
= 1.17 m/sec
avg velocity =
final displacement - initial displacement/2
since pool is 70m long only...after swimming 140m....the final position will be the same as starting position so 0 displacement
= 0 - 0/2
= 0m/s
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