Question

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Answer 1

$\orange{ \mid{ \underline{ \overline{ \tt 301 \: \: is \: a \: term \: of \: the \: given \: AP.}} \mid}}$

Step-by-step explanation:

AP = 5,11,17,23..

then,

a = 5 & d= 11-5=6

an = a + (n-1)d

301 = 5+(n-1)(6)

301= 5 + 6n -6

301 = 6n -1

301-1 = 6n

300 = 6n

300/6 = n

50 = n

Therefore 301 is a term of the list of the given AP.

I hope this will help you

Answer 2

Answer:

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