Question

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Answer 1

Step-by-step explanation:

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Answer 2

$\Large{\underbrace{\sf{\orange{Required\:Solution:}}}}$

$\displaystyle{\sf{ \dfrac{2x+1}{3x-2} = \dfrac{9}{10}}}$

• Do cross multiplication.

$\longrightarrow{\sf{ 10(2x+1) = 9(3x-2)}}$

• Open the brackets and multiply the numbers.

$\longrightarrow{\sf{ 20x+10 = 27x - 18}}$

• Transpose 27x to L.H.S and 10 to R.H.S.

$\longrightarrow{\sf{20x-27x=-18-10}}$

$\longrightarrow{\sf{-7x=-28}}$

$\longrightarrow{\sf{ \cancel{-}7x = \cancel{-}28}}$

$\longrightarrow{\sf{ 7x = 28}}$

$\longrightarrow{\sf{x = \dfrac{28}{7}}}$

:$\large\implies{\boxed{\sf{\orange{x = 4}}}}$

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