Physics, asked by supriyasingh964833, 6 hours ago

plz explain above question and follow my intro​

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Answered by vasukumar1989k
1

Answer:

hope you like my explanation

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Answered by itsPapaKaHelicopter
1

Answer:-

In the given figure, we need to extend the line OP to intersect RQ at X.

Since, we know that OP // RS and RX is a

transversal so by the property of alternate angles,

we have,

∠RXP = ∠ XRS

It is given that QRS = 130°

∠RXP  = 130°

Since, RQ is a line segment and applying the linear pair axiom,

we get,

∠PXQ+∠RXP = 180°

⇒∠PXQ = 180° -∠RXP

⇒∠PXQ = 180° – 130°

⇒∠PXQ = 50°

Now in APQX, we know that the exterior angle is

equal to sum of opposite interior angles.

∠OPQ = ∠PXQ + ∠PQX

⇒110° = 50° + ∠ PQX

⇒∠PQR = 110° - 50°

⇒∠PQR = 60°

 \textbf{Hence, the value is 60°.}

  • and correct option is (c)60°

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