Question

plz explain above question and follow my intro​

Answer 1

Answer:

hope you like my explanation

Answer 2

Answer:-

In the given figure, we need to extend the line OP to intersect RQ at X.

Since, we know that OP // RS and RX is a

transversal so by the property of alternate angles,

we have,

$∠RXP = ∠ XRS$

It is given that QRS = 130°

$∠RXP = 130°$

Since, RQ is a line segment and applying the linear pair axiom,

we get,

$∠PXQ+∠RXP = 180°$

$⇒∠PXQ = 180° -∠RXP$

$⇒∠PXQ = 180° – 130°$

$⇒∠PXQ = 50°$

Now in APQX, we know that the exterior angle is

equal to sum of opposite interior angles.

$∠OPQ = ∠PXQ + ∠PQX$

$⇒110° = 50° + ∠ PQX$

$⇒∠PQR = 110° - 50°$

$⇒∠PQR = 60°$

$\textbf{Hence, the value is 60°.}$

• and correct option is (c)60°

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