plz explain/answer the following problem
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Answer:
trapezoid area= 1/2×(sum of parallel sides)× height
108=1/2×(15+12)×h
108=1/2×27×h
108×2/27=h
h= 8 yd
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Answered by
1
Step-by-step explanation:
We know ar(Trapezoid)= 1/2×(sum of parallel side)×h
According to question,
ar(Trapezoid)= 108yd
Now,1/2×(15+12)×h=108
13.5h=108
h=8 yd
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