Question

plz explain full and send fast

Answer 1

this is a very easy conceptual question ....
PROCEDURE :-
Pythagoras theorem => ( Hypotenuse )^2 = ( Base )^2 + ( perpendicular )^2...
first use Pythagoras theorem in triangle ABP to find length of AP then use Pythagoras theorem in triangle DCP to find length of PC...
add AD and PC you will get required answer .......
SOLUTION :-
using Pythagoras theorem in triangle APC
(17)^2 = (8)^2+(AP)^2
AP=15 m
using Pythagoras theorem in triangle DCP.
(17)^2=(15)^2+(PC)^2
PC=8.
Now total width of the street = AP+PC
=15+8 = 24 m......

Hope you understand...
plz mark as brainlist...

Answer 2

Using Pythagoras theorem

in ∆ABP

(AP)^ =BP^2 -AB^2

(AP)^2 = 289-64
AP =√225
AP =15
__________________________________
in ∆ CPD

PC^2 = PD^2 -CD^2

PC ^2=(289 -225)

PC= √64

PC=8

width of the street = AP +PC =15+8=23 m

$23$