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let us assume that root3 is rational
so now root3 can be written in p/q form where p and q (q not equal to 0) are coprime( no common factor other than 1)
hence
p = root 3q
now squaring both sides
( root 3q)square= p square
or, 3q square= p square______(1)
p square/3 =q square
therefore 3 is a factor of p
p=3c( where c is a constant)
substituting p=3c in equation 1,
( 3c )square= 3q square
or, 9c square= 3q square
or, 3c square= q square
or, c square= q square/3
therefore 3 is also a factor of q. but this is a contradiction.
therfore root3 is an irrational number.( proved )
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