Question

PLZ EXPLAIN THE ANSWER
VERY URGENT
PLZ​

Answer 1

Answer:

34°

Step-by-step explanation:

A rhombus has opposite angles equal

therefore angle R= angle P

and angle S= angle Q

(Let S and Q be x)

By angle sum property of a quadrilateral

angle P + angle Q + angle R + angle S = 360°

72+x+72+x=360

144+2x= 360

2x= 360-144

2x= 216

x= 216/2

x= 108

therefore angle S= angle Q= 108°

seg. SQ bisects angle Q

So angle SQP= 1/2 angle Q

108×1/2=54°

If we observe carefully,

seg PQ intersects seg ST making angles in a linear pair. And sum of angles in a linear pair is 180°

So, angle SQP =54° (proved)

angle SQP+ angle PQT = 180° (Linear pair angles)

54+ angle PQT = 180°

angle PQT = 180-54

angle PQT = 126°.

Let us consider triangle PQT

AngleP+angle Q+angle T= 180° (angle sum property of triangle)

20+126+angle T= 180

146+angle T= 180

angle T= 180-146

angle T= 34°

therefore y= 34°

hope it helps :)