Question

plz explain this ans​

Answer 1

Answer:

90 answers as that makeing right angle

Answer 2

Solution:-Let us first take out the magnitude of (VectorA+VectorB) and (VectorA-VectorB)

|A+B|=(A^2+B^2+2ABcos∅)^1/2

|A-B|=(A^2+B^2-2ABcos∅)^1/2

also,

A=B and ∅=90

|A+B|=(2A^2+2A^2×0)^1/2=A√2

|A-B|=(2A^2-2A×0)^1/2=A√2

now here,we are seeing that, |A+B| and |A-B| are equal so

|A+B|=|A-B|

(A^2+B^2+2ABcos∅)^1/2=(A^2+B^2-2ABcos∅)^1/2

4ABcos∅=0

cos∅=0

cos∅=cos90

∅=90

hence angle between them will be 90