Math, asked by shivam8815358034, 6 months ago

plz factorise it briefly with full explanation​

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Answers

Answered by ydwijay
0

Answer:

very easy question

Step-by-step explanation:

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Answered by Anonymous
4

Answer:

➝ 4x² + y² + z² - 4xy - 2yz + 4xz

➝ 2²x² + y² + z² - 4xy - 2yz + 4xz

➝ (2x)² + y² + z² - 4xy - 2yz + 4xz

➝ (2x)² + (y)² + (z)² - 2(2x) (y) + 2 (-y) (z) + 2 (2x) (z)

Using (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ac

➝ [2x + (-y) + z]²

➝ [2x - y + z]²

[2x - y + z] [2x - y + z]

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\boxed{\begin{minipage}{7 cm}\boxed{\underline{\underline{\bigstar\:\bf\:Algebric\:Identity\:\bigstar}}}\\\\ \sf 1] (a+b)^{2} = a^{2} + 2ab + b^{2}\\\\ \sf 2] (a-b)^{2} = a^{2} - 2ab + b^{2}\\\\ \sf 3] a^{2} - b^{2} = (a+b)(a-b)\\\\ \sf 4] (a+b)^{2} = (a-b)^{2} + 4ab\\\\ \sf 5] (a-b)^{2} = (a+b)^{2} - 4ab\\\\ \sf 6] (a+b)^{3} = a^{3} + 3ab(a+b) + b^{3}\\\\ \sf 7](a-b)^{3} = b^{3} - 3ab(a-b) + b^{3}\\\\ \sf 8] a^{3} + b^{3} = (a+b)(a^{2} - ab + b^{2})\\\\9] a^{3} - b^{3} = (a-b)(a^{2} + ab + b^{2})\\\\10] (a+b+c)^{2} = a^{2} + b^{2} + c^{2} + 2(ab+ bc + ca)\\\\\end{minipage}}

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