Question

Plz fairly and fastly answer Q 30 ~ points 50

Answer 1

By using phythagoras theorem we have
AC2 = AB2+BC2
a2+b2
= under root a2+b2
answer is not conform

Answer 2

let the side of the square be = x

the square be named as DEFB where DE=EF=FB=DB=x

(point D lies on side AB , E on side AC and F on side BC)

now,

AD=a-x

FC=b-x

by RHS triangle ADE is similar to triangle EFC

therefore AD/DE=EF/FC

a-x/x=x/b-x

ab-ax-bx+x^2=x^2

ab=x(a+b)

x=ab/a+b