Question

plz fast correct with complet explanation​

Answer 1

Heya Mate ur answer is....

A year has 52 weeks and 1 day

So, in that one day can be any of the seven days.

So the probability is..

P(ls)=No. of outcomes/ No. of possible events.

= 1/7
Considering a leap year
leap year contains 366 days
52 weeks plus two two extra days
52 weeks means definitely there are 52 sundays (this is true for all other days also).
if either of these two is sunday then we will have 53 sundays
these two days can be {mon, tue} or { tue , wed} or { wed , thurs} or {thurs , fri} or { fri, sat} or { sat , sun} or {sun , mon} i.e total =7
out of these only two outcomes i.e { sat , sun} and {sun , mon} is having sunday with them .
so our desired prob is 2/7.

Hope it helps...

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Answer 2

in an leap year there are 366 days out of which 2 days can't be grouped as seven days (as a week) .

let S be the sample space of days in a leap year.(as there are seven days in a week)

n(S)=7

let A be the event of getting 53 Sundays in an leap year.

(A)={(sun,mon),(Mon,tue),(Tue,wed),(wed,thu),(Thu,fri),(Fri,sat),(sat,sun)}

n(A)=2

p(A)=n(A)/n(S)

p(A)=2/7

I hope this helps you. . . .