Question

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Answer 1

Answer:

$( \frac{x}{y} ) = ( \frac{ - 1}{3} ) {}^{ - 1} + ( \frac{2}{3} ) {}^{ - 4}$

$\frac{x}{y} = - 3 + (\frac{3}{2} ) {}^{4}$

$\frac{x}{y} = - 3 + \frac{81}{16}$

$\frac{x}{y} = \frac{ - 48 + 81}{16} = \frac{33}{16}$

a)

$(\frac{x}{y} ) {}^{ - 1} = \frac{y}{x} = \frac{33}{16}$

b)

$(\frac{x}{y} + \frac{y}{x} ) {}^{ - 1} = ( \frac{33}{16} + \frac{16}{33} ) {}^{ - 1} =( \frac{1089 +256 }{528} ) {}^{ - 1} =( \frac{1345}{528} ) { }^{ - 1} = \frac{528}{1345}$

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