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physics class 10th...?????????
piyushkr7:
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Answer:
equivalent resistance =2.55r
Explanation:
R1 and R2 are connected in series.
therefore, R1+R2 (R')= 2r + 4r
=6r
again, R4 and R5 are also connected in series.
Therefore, R4 + R5(R") = 7r + 10r
17r
Now, R' , R" and R3 are connected in parallel combination.
Therefore, the equivalent resistance (R) will be -
1/R = 1/R' + 1/R" + 1/R3
=1/6r + 1/17r + 1/6r
= 17r + 6r +17r/ 102r
= 40r/102r
now,
R= 102r /40r
=2.55
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