Question

plz fast ..... urgent
​

Answer 1

physics class 10th...?????????

Answer 2

Answer:

equivalent resistance =2.55r

Explanation:

R1 and R2 are connected in series.

therefore, R1+R2 (R')= 2r + 4r

=6r

again, R4 and R5 are also connected in series.

Therefore, R4 + R5(R") = 7r + 10r

17r

Now, R' , R" and R3 are connected in parallel combination.

Therefore, the equivalent resistance (R) will be -

1/R = 1/R' + 1/R" + 1/R3

=1/6r + 1/17r + 1/6r

= 17r + 6r +17r/ 102r

= 40r/102r

now,

R= 102r /40r

=2.55