Question

plz......fastttttttttttttttt

Answer 1

AD = 1cm

BD = 2 cm

AB = AD +BD = 3 cm

$\frac{ar(ABC)}{ar(ADE)} = \frac{AB^{2} }{AD^{2} }$

$\frac{ar(ABC)}{ar(ADE)} = 3^{2}/1$

ar(ABC):ar(ADE) = 9:1