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Answers
Answer:
2) Given: 51 g of NH3
i) molecular mass = N = 14g
= H = 1 ×3 = 3g
= 14 + 3 = 17g
ii)number of moles = given mass × 1 mol
mass in 1 mol of NH3
= 51 × 1 mol
17
= 3 moles
iii) number of molecules =
given moles (the previous answer)× 6.02 × 10^23
= 3 × 6.02 × 10^23
iv) number of atoms =
number of moles × 6.02 × 10^23
= 3 × 6.02 × 10^23
3) given: 56g of N2
i) number of moles = given mass × 1 mol
mass in 1 mol of N2
= 56 × 1mol
28
= 2 moles
ii)number of molecules =
given moles (the previous answer)× 6.02 × 10^23
= 2 × 6.02 × 10^23
iii)number of atoms =
number of moles × 6.02 × 10^23
= 2 × 6.02 × 10^23
4) given: 96g of O2
i)number of moles = given mass × 1 mol
mass in 1 mol of O2
= 96 × 1 mol
32
= 3 moles
ii)number of atoms =
number of moles × 6.02 × 10^23
= 3 × 6.02 × 10^23
5) given :36g of H2O
i) molecular mass = H = 1×2 =2
= O = 16 = 16
= 16 + 2 = 18g
ii) number of moles = given mass × 1 mol
mass in 1 mol of H2O
= 36 × 1 mol
18
= 2 moles
iii)number of molecules =
given moles (the previous answer)× 6.02 × 10^23
= 2 × 6.02 × 10^23
iv)number of atoms =
number of moles × 6.02 × 10^23
= 2 × 6.02 × 10^23
hope this helps you :)