Question

plz find the correct option ​

Answer 1

$\mathfrak{\large{\underline{\underline{\red{Question :-}}}}}$

Find the value of :

$\tt{\dfrac{2\dfrac{1}{3} \times 4 \dfrac{1}{4} - 4 \dfrac{1}{6} \div 6 \dfrac{1}{4}}{3 \dfrac{1}{3} \div 4 \dfrac{1}{4} \times 5 \dfrac{2}{3} }}$

$\mathfrak{\large{\underline{\underline{\red{Answer :-}}}}}$

Option (b)

$\tt \:2 \dfrac{13}{160}$

$\mathfrak{\large{\underline{\underline{\red{Explanation :-}}}}}$

$\implies\tt{\dfrac{2\dfrac{1}{3} \times 4 \dfrac{1}{4} - 4 \dfrac{1}{6} \div 6 \dfrac{1}{4}}{3 \dfrac{1}{3} \div 4 \dfrac{1}{4} \times 5 \dfrac{2}{3}}}$

$\tt{\implies} \: \dfrac{\dfrac{7}{3} \times \dfrac{17}{4} - \dfrac{25}{6} \div \dfrac{25}{4}}{\dfrac{10}{3} \div \dfrac{17}{4} \times \dfrac{17}{3}}$

$\tt{\implies} \: \dfrac{\dfrac{7}{3} \times \dfrac{17}{4} - \dfrac{\cancel{25}}{6} \times \dfrac{4}{\cancel{25}}}{\dfrac{10}{3} \times \dfrac{4}{\cancel{17}} \times \dfrac{\cancel{17}}{3}}$

Cancel 25 and 17.

$\tt{\implies} \: \dfrac{\dfrac{7}{3} \times \dfrac{17}{4} - \dfrac{4}{6}}{\dfrac{10}{3} \times \dfrac{4}{3}}$

$\tt{\implies} \: \dfrac{\dfrac{119}{12} - \dfrac{4}{6}}{\dfrac{40}{9}}$

$\tt{\implies} \: \dfrac{\dfrac{119 - 8}{12}}{\dfrac{40}{9}}$

$\tt{\implies} \: \dfrac{\dfrac{111 }{12}}{\dfrac{40}{9}}$

$\tt{\implies} \: \dfrac{111}{12} \times \dfrac{9}{40}$

$\tt{\implies} \: \dfrac{999}{480}$

Convert into mixed fraction

$\tt{\implies} \:2 \dfrac{13}{160}$

$\therefore$ The answer is :

Option (b)

$\tt \:2 \dfrac{13}{160}$

Answer 2

$\frac{2 \frac{1}{3} \times 4 \frac{1}{4} - 4 \frac{1}{6} \div 6 \frac{1}{4} }{3 \frac{1}{3} \div 4 \frac{1}{4} \times 5 \frac{2}{3} } \\ \\ \frac{ \frac{7}{3} \times \frac{17}{4} - \frac{25}{6} \div \frac{25}{4} }{ \frac{10}{3} \div \frac{17}{4} \times \frac{17}{3} }$

According to Rule of BODMAS

Division Work should be Done first

$\frac{ \frac{7}{3} \times \frac{17}{4} - \frac{25}{6} \div \frac{25}{4} }{ \frac{10}{3} \div \frac{17}{4} \times \frac{17}{3} } \\ \\ \frac{ \frac{7}{3} \times \frac{17}{4} - \frac{ \cancel{25}}{6} \times \frac{4}{ \cancel{25}} }{ \frac{10}{3} \times \frac{4}{ \cancel{17} } \times \frac{ \cancel{17}}{3} } \\ \\ \frac{ \frac{119}{12} - \frac{4}{6} }{ \frac{10}{3} \times \frac{4}{3} } \\ \\ \frac{ \frac{119 - 4 \times 2}{12} }{ \frac{40}{9} } \\ \\ \frac{ \frac{119 - 8}{12} }{ \frac{40}{9} } \\ \\ \frac{ \frac{111}{12} }{ \frac{40}{9} } \\ \\ \frac{111}{12} \times \frac{9}{40} \\ \\ \frac{111}{4} \times \frac{3}{40} \\ \\ \frac{333}{160} \\ \\ 2 \frac{13}{160}$

So Right Option is (B)

$\boxed{ \red{ \huge 2 \frac{13}{160} }}$